tolong dibantu dan isikan cara pengerjaan nya,yang asal auto reportt!
1. v = 40 m/s
r = 20 cm = 0.2 m
a. Frekuensi putaran
w (omega) = kecepatan sudut
w = v/r
= 40/0.2
= 200 rad/s
w = 2×pi×f
f = w/2pi
= 200/2×pi
= 100/pi Hz
b. Periode putaran
T = 1/f
= 1/(100/pi) = pi/100 sekon
c. kexepatan sudut = w = 200 rad/s
d. Percepatan sentripetal
a = (v^2)/r
= (40^2)/0.2
= 8000 m/s^2
2. r = 50 cm = 0.5 m
w (omega) = 1200 rpm = 125.66 rad/s
a. f = w/(2×pi)
= 125.66/2pi
= 62.83/pi Hz
b. T= 1/f
= pi/62.83 sekon
c. v = w×r
= 125.66 × 0.5 = 62.83 m/s